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Thursday, 16 October 2014

New Question paper Pattern of CBSE UGC NET December 2014

Recently central board of secondary education CBSE, has published the official Notification regarding the UGC university grant commission, NET national Eligibility Test Examination 2014 and JRF junior research fellowship.  This UGC got the responsibility for conducting the NET / JRF Examination. Online registration process has been started from 15 October 2014 at the official website of CBSE NET which is http://cbsenet.nic.in/cbsenet/welcome.aspx
 On behalf of UGC, the Central Board of Secondary Education announces holding of the National Eligibility Test (NET) on 28th Dec 2014 (SUNDAY) for determining the eligibility of Indian nationals for the Eligibility for Assistant Professor only or Junior Research Fellowship & Eligibility for Assistant Professor Both in Indian universities and colleges. CBSE will conduct NET in 79 subjects (listed under item no. 9) at 89 selected NET Coordinating Institutions (listed under Item no. 10) spread across the country.
Every year many lakh candidates are appearing in this examination. so guys start your preparation if you want to crack CBSE UGC NET Examination. this time CBSE is now going to conduct the examination so its sure question paper will not be easy just like CTET examination.  So without a proper strategy, a solid plan it would be difficult to qualify in this examination.  

Revised question paper pattern | CBSE UGC Net DEC Exam Syllabus
Session
Paper
Marks
No of Questions
Time Duration
First
I
100
60 out of which 50 question to be attempted
1¼ Hours (09.30 A.M. to 10.45 A.M.)
First
II
100
50 questions all are compulsory
1¼ Hours (10.45 A.M. to 12.00 NOON)
Second
III
150
75 questions all are compulsory
2 1/2 Hours (01.30 P.M. to 4.00 P.M.)

Question paper 1 of CBSE UGC NET Exam December 2014 : teaching/research aptitude ,   reasoning ability, comprehension, divergent thinking and general awareness

Question Paper 2 :  shall consist of 50 objective type compulsory questions based on the subject selected by the candidate. Each question will carry 2 marks.
Question Paper3:  will consist of 75 objective type compulsory questions from the subject selected by the candidate. Each question will carry 2 marks.

PROCEDURE & CRITERIA FOR DECLARATION OF RESULT:
This will comprise of following steps:
Step I: Minimum marks to be obtained in NET for considering a candidate for the award of JRF and eligibility for Assistant Professor:
The candidates are required to obtain following minimum marks separately in Paper-I, Paper-II and Paper-III as given below:
Category
Minimum marks %

Paper I
Paper II
Paper III
General
40 (40%)
40 (40%)
75 (50%)
OBC , PWD, SC, ST
35 (35%)
35  (35%)
60 (40%)
Step II: Amongst those candidates who have cleared step I, a merit list will be prepared subject-wise and category-wise using the aggregate marks of all the three papers secured by such candidates.
Step III: Top 15% candidates (for each subject and category), from the merit list mentioned under step II, will be declared NET qualified for eligibility for Assistant Professor only.
Step IV: A separate merit list for the award of JRF will be prepared from amongst the NET qualified candidates figuring in the merit list prepared under step III. It may be noted that the above qualifying criteria decided by UGC/CBSE is final and binding.

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