Recently central board of secondary education CBSE, has
published the official Notification regarding the UGC university grant commission,
NET national Eligibility Test Examination 2014 and JRF junior research fellowship.
This UGC got the responsibility for
conducting the NET / JRF Examination. Online registration process has been
started from 15 October 2014 at the official website of CBSE NET which is http://cbsenet.nic.in/cbsenet/welcome.aspx
On behalf of UGC,
the Central Board of Secondary Education announces holding of the National
Eligibility Test (NET) on 28th Dec 2014 (SUNDAY) for determining the
eligibility of Indian nationals for the Eligibility for Assistant Professor
only or Junior Research Fellowship & Eligibility for Assistant
Professor Both in Indian universities and colleges. CBSE will conduct NET
in 79 subjects (listed under item no. 9) at 89 selected NET Coordinating
Institutions (listed under Item no. 10) spread across the country.
Every year many lakh candidates are appearing in this examination.
so guys start your preparation if you want to crack CBSE UGC NET Examination.
this time CBSE is now going to conduct the examination so its sure question
paper will not be easy just like CTET examination. So without a proper strategy, a solid
plan it would be difficult to qualify in this examination.
Revised question paper pattern | CBSE UGC Net DEC Exam
Syllabus
Session
|
Paper
|
Marks
|
No of Questions
|
Time Duration
|
First
|
I
|
100
|
60 out of which 50 question to be attempted
|
1¼ Hours (09.30 A.M. to 10.45 A.M.)
|
First
|
II
|
100
|
50 questions all are compulsory
|
1¼ Hours (10.45 A.M. to 12.00 NOON)
|
Second
|
III
|
150
|
75 questions all are compulsory
|
2 1/2 Hours (01.30 P.M. to 4.00 P.M.)
|
Question paper 1 of CBSE UGC NET Exam December 2014 : teaching/research
aptitude , reasoning ability, comprehension, divergent
thinking and general awareness
Question Paper 2 : shall consist of 50 objective type
compulsory questions based on the subject selected by the candidate. Each
question will carry 2 marks.
Question Paper3: will
consist of 75 objective type compulsory questions from the subject selected
by the candidate. Each question will carry 2 marks.
PROCEDURE & CRITERIA FOR DECLARATION OF RESULT:
This will comprise of following steps:
Step I: Minimum marks to be obtained in NET for
considering a candidate for the award of JRF and eligibility for Assistant
Professor:
The candidates are required to obtain following minimum
marks separately in Paper-I, Paper-II and Paper-III as given below:
Category
|
Minimum marks %
|
||
Paper I
|
Paper II
|
Paper III
|
|
General
|
40 (40%)
|
40 (40%)
|
75 (50%)
|
OBC , PWD,
SC, ST
|
35 (35%)
|
35 (35%)
|
60 (40%)
|
Step II: Amongst those candidates who have cleared step
I, a merit list will be prepared subject-wise and category-wise using the
aggregate marks of all the three papers secured by such candidates.
Step III: Top 15% candidates (for each subject and
category), from the merit list mentioned under step II, will be declared
NET qualified for eligibility for Assistant Professor only.
Step IV: A separate merit list for the award of JRF will
be prepared from amongst the NET qualified candidates figuring in the merit
list prepared under step III. It may be noted that the above qualifying
criteria decided by UGC/CBSE is final and binding.
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